4m^2=(m-4)(2-m)

Solution for 4m^2=(m-4)(2-m) equation:

4m^2=(m-4)(2-m)

We move all terms to the left:

4m^2-((m-4)(2-m))=0

We add all the numbers together, and all the variables

4m^2-((m-4)(-1m+2))=0

We multiply parentheses ..

4m^2-((-1m^2+2m+4m-8))=0


We calculate terms in parentheses: -((-1m^2+2m+4m-8)), so:

(-1m^2+2m+4m-8)

We get rid of parentheses

-1m^2+2m+4m-8

We add all the numbers together, and all the variables

-1m^2+6m-8

Back to the equation:

-(-1m^2+6m-8)


We get rid of parentheses

4m^2+1m^2-6m+8=0

We add all the numbers together, and all the variables

5m^2-6m+8=0

a = 5; b = -6; c = +8;
Δ = b2-4ac
Δ = -62-4·5·8
Δ = -124
Delta is less than zero, so there is no solution for the equation